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Svetlanka [38]
2 years ago
14

Please answer this correctly without making mistakes

Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:

2 pt + 1c

Step-by-step explanation:

There are 2 cups in a pint. So, 2c = p, dividing 2 from both sides, we get

c = (1/2)p

Replace c with 1/2 p in the equation

5 pt - (2pt + (1/2)p)

= 5pt - 2pi - (1/2)p

= 3pt  - (1/2)p

= 2pt  + (1/2)p

Replace back (1/2)p for c

2pt  + (1/2)p =

2 pt + 1c

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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

                                        2(2-y)-y=1\\4-2y-y=1\\4-3y=1\\-3y=1-4\\-3y=-3\\y=1

Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
Please help!!!!
Yakvenalex [24]

Answer:

  D.  X-7

Step-by-step explanation:

The table tells you that when x=7, g(x) = 0. In order for g(7) to be zero, at least one factor must be zero when x=7. The only factor on the list that is zero when x=7 is (x-7).

6 0
3 years ago
Which statement correctly describes the graph of y = x + 9.5?
Vikki [24]

Answer:

A is the answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for x: |x|-8=-5
xxMikexx [17]

x*-8 would be -8x

then you would divide -8 by both sides

should get a decimal as your answer I believe

4 0
3 years ago
Read 2 more answers
What is the product of 2x-5 and 3x2 + 5x - 7? Write your answer in standard form.
jasenka [17]

Step-by-step explanation:

this is your answer..........

5 0
3 years ago
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