40.0*10 is the answer
actually it is 400 but u want in decimal so it is 40.0*10
BC and BCE are Before Common Era
So what you want to do is add 1952 and 384
1952 + 384 = 2336
So the amount of years between 384 BC and 1952 AD is about 2,336 years
Hope this helps
45 ÷ 3 = 15
21 ÷ 3 = 7
12 ÷ 3 = 4
(4 + 15) x 7 = 133
OR if you’re using bedmas/pedmas
4 + (15 x 7) = 109
2.77*10^3+1.04^10^4
2.77*10^3=2770 where (10^3=1000, so 1000*2.77)
1.04*10^4=10400 where (10^4=10000, so 10000*1.04)
2770+10400
=13170
Answer:
The easiest way of solving this is to eliminate one of the variables. If you multiply each of the equations by a number so you can add the equations together and have only one variable left, you can solve the single variable equation. Try multiplying the first equation by 11, the second by -10 and adding them, thus eliminating the y variable. After this, substitute that value you have for x and solve for y. I hope this helps.
Step-by-step explanation:
