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lawyer [7]
3 years ago
9

Can someone tell me the answer 1)1547 2)2750 3)36835 round off each of the following number to a) the nearest ten b) the nearest

hundred c) the nearest thousand
Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

1550, 2760, 36840 that s all

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Evaluate: (d + 1)(d - 1 + 6) <br> d = 2
Allisa [31]
F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21
3 0
3 years ago
Tom and Kathy want to borrow $35,000 in order to build an addition to their home.
Novosadov [1.4K]

Answer:

I think its C you can hate how much you want if I'm wrong im more of a no tester when I get an answer i check but not online

Step-by-step explanation:

7 0
3 years ago
30 tens = ones<br> 30 tens = hundreds
Svetllana [295]

30 tens = 30 x 10 = 300

300 ones = 300 x 1 = 300

300 is your answer

30 tens = 30 x 10 = 300

3 hundreds = 3 x 100 = 300

3 is your answer

<em>~Rise Above the Ordinary</em>

4 0
3 years ago
which of the following equations represents a linear function? A. y=3X^2 B. Y=2- 6/x C. y= x +6 D.y=1/2x+3
grigory [225]
<span> C. y= x +6 is the linear equation</span>
4 0
3 years ago
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
3 years ago
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