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3 years ago

PLS HELP!! WILL GIVE BRAINLIEST!!

Mathematics

1 answer:

Inessa [10]3 years ago

6 0

Answer:

Step-by-step explanation:

take lcm of (2x-1)(x+2)

lcm=(2x-1)(x+2)

=2(x+2)-1(2x-1)/(2x-1)(x+2)

=(2x+4)-(2x-1)/(2x(x+2)-1(x+2)

=2x+4-2x+1/2x^2+4x-x+2

=4+1/2x^2+3x+3

=5/2x^2+3x+3

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Johnny wrapped a piece of string around a can of soup. If the soup's diameter was 4 inches, how long was the string? Find the ci

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Find the sum of 2/5 and 3/10

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Answer: 7/10

Explanation:

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Which graphs show continuous data? Select each correct answer. 50 points

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4 years ago

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Х- а x-b If f(x) = b.x-a÷b-a + a.x-b÷a - b Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

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3 years ago