Answer:
Average rate of change over the interval 2<= x <= 5:
y = 3x + 5: 3
y = 3x^2 + 1: 21
y = 3^x: 78
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Step-by-step explanation:
2<= x <= 5
Average rate of change over the interval 2<= x <= 5:
<u>y = 3x + 5</u>
y(5) = 3(5) + 5 = 20
y(2) = 3(2) + 5 = 11
Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>
<u />
<u>y = 3x^2 + 1</u>
y(5) = 3(5^2) + 1 = 75 + 1 = 76
y(2) = 3(2^2) + 1= 13
Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>
<u />
<u>y = 3^x</u>
y(5) = 3^5 = 243
y(2) = 3^2 =9
Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>
Answer:
The probability that he teleports at least once a day = ![\mathbf{\frac{5}{9}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cfrac%7B5%7D%7B9%7D%7D)
Step-by-step explanation:
Given -
Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.
Total no of outcomes = 3
P( He not choose teleport in the morning ) = ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
P( He not choose teleport in the evening ) = ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )
= 1 - P( He not choose teleport in the morning )
P( He not choose teleport in the evening )
= ![1 - \frac{2}{3}\times\frac{2}{3}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B2%7D%7B3%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D)
= ![\frac{5}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D)
This seems like a personal question
Answer:
x>4
Step-by-step explanation:
x+3>19-3x
x+3x>19-3
4x>16
x>4