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sineoko [7]
3 years ago
6

What is the number in scientific notation? ​0.000013

Mathematics
2 answers:
leva [86]3 years ago
5 0
13^6 you whould have to move the decimal over 6 times :)
Eduardwww [97]3 years ago
5 0
1.3X10^-5 is your answer
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AAST is dilated about the origin o to create ARST. Point Ris located at (3.9) and point R’ is
Slav-nsk [51]

The scale factor which used to perform the dilation was 0.4

Step-by-step explanation:

If point (x , y) is dilated about the origin by a scale factor k, then

  • Its image is point (kx , ky)
  • If k > 1, then kx > x and ky > y
  • If 0 < k < 1, then kx < x and ky < y

∵ Δ RST is dilated about the origin O to create Δ R'S'T'

- Assume that the scale factor is k

∵ Point R is (3 , 9)

∴ x = 3 and y = 9

∵ Point R' is (1.2 , 3.6)

∴ kx = 1.2 and ky = 3.6

∵ x = 3 and kx = 1.2

- Substitute x in kx to find k

∴ k(3) = 1.2

∴ 3k = 1.2

- Divide both sides by 3

∴ k = 0.4

To check your answer use the y-coordinates of R and R' to find k

∵ y = 9 and ky = 3.6

- Substitute the value of y in ky to find k

∵ k(9) = 3.6

∴ 9k = 3.6

- Divide both sides by 9

∴ k = 0.4

∴ The scale factor is 0.4

The scale factor which used to perform the dilation was 0.4

Learn more:

You can learn more about dilation in brainly.com/question/3552621

#LearnwithBrainly

5 0
3 years ago
Someone please help I don’t understand this please
sdas [7]

The fraction of the image in blue with respect to the <em>entire</em> hexagon is \frac{1}{3}.

<h3>Estimation of the ratio of the shaded region area to the entire area</h3>

Initially we proceed to create auxiliar constructions , represented by red line segments, to re-define the hexagon as a sum of standard figures. According to the figure, we find two types of triangles (type-1 and type-2), and the following relationship between the two types:

A_{1} = A_{2} (1)

Where:

  • A_{1} - Area of a type-1 triangle.
  • A_{2} - Area of a type-2 triangle.

The formulae for the area of the shaded region (A_{s}) and the <em>entire</em> hexagon (A_{h}) are, respectively:

<h3>Shaded region</h3>

A_{s} = 2\cdot A_{1} + 4\cdot A_{2} (2)

<h3>Entire hexagon</h3>

A_{h} = 8\cdot A_{1} + 10\cdot A_{2} (3)

And the fraction of the image in blue is:

\frac{A_{s}}{A_{h}} =  \frac{2\cdot A_{1}+4\cdot A_{2}}{8\cdot A_{1}+10\cdot A_{2}}

\frac{A_{s}}{A_{h}} = \frac{6\cdot A}{18\cdot A}

\frac{A_{s}}{A_{h}} = \frac{1}{3}

The fraction of the image in blue with respect to the <em>entire</em> hexagon is \frac{1}{3}. \blacksquare

To learn more on hexagons, we kindly invite to check this verified question: brainly.com/question/4083236

6 0
3 years ago
Graph f(x) = x2 + 2x - 3, label the function’s x-intercepts, y-intercept and vertex with their coordinates. Also draw in and lab
Semenov [28]
<h2>Answer with explanation:</h2>

The given function : f(x)=x^2+2x-3

Using completing the squares, we have

f(x)=x^2+2x+1-1-3        [∵ (x+1)^2=x^2+2x+1]

f(x)=(x+1)^2-4      (1)

Comparing (1) to the standard vertex form f(x)=(x-h)^2+k , the vertex of function is at (h,k)=(-1,-4)

For x-intercept, put f(x)=0 in (1), we get

0=(x+1)^2-4\\\\\Rightarrow\ (x+1)^2=4    

Square root on both sides, we get

x+1=\pm2\\\\x+1=-2\ or\ \ x+1=2\\\\=x=-3\ \ or\ x=1

∴ x intercepts : x= (-3,0) and (1,0)

For y-intercept put x=0 in (1), we get

f(1)=(1)^2-4=1-4=-3  

∴ y intercept : (0,-3)

Axis of symmetry : \dfrac{-b}{2a}

In f(x)=x^2+2x-3 , a=1 and b=2

Axis of symmetry=\dfrac{-2}{2(1)}=-1

5 0
3 years ago
If the measure of ÐDCB = 100°, and ÐDAC = 20°, what is ÐCAB?
Arisa [49]
DCAB would be 100. I'm pretty sure DCAB would be 100 because if DDAC is 20 that means the letters D,C, and A are 5. So if D,C, and A are all equal to 5 then B is equal to 85.

8 0
3 years ago
Ms.Gartland bought x number of shirts for the new members of her chorus.The cost for x number of shirts,including $3.99 shipping
lorasvet [3.4K]

1

77.49 - 3.99 = $73.5

73.5 / 12.25 = 6 Shirts

6 0
3 years ago
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