Problem 1
<h3>Answers:</h3><h3>angle 6 = 50</h3><h3>angle 7 = 50</h3><h3>angle 8 = 40</h3>
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Work Shown:
point E = intersection point of diagonals.
x = measure of angle 6
y = measure of angle 8
angle 7 is also x because triangle AED is isosceles (AE = ED)
Focus on triangle AED, the three angles A, E, D add to 180
A+E+D = 180
x+80+x = 180
2x+80 = 180
2x = 180-80
2x = 100
x = 100/2
x = 50
So both angles 6 and 7 are 50 degrees.
Turn to angle 8. This is adjacent to angle 7. The two angles form a 90 degree angle at point A. This is because a rectangle has 4 right angles.
(angle7)+(angle8) = 90
50+y = 90
y = 90-50
y = 40
angle 8 = 40 degrees
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Problem 2
<h3>Answers:</h3><h3>angle 2 = 61</h3><h3>angle 3 = 61</h3>
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Work Shown:
Angle 5 is 29 degrees (given). So is angle 4 because these are the base angles of isosceles triangle DEC (segment DE = segment EC)
angle 3 and angle 4 form a 90 degree angle
x = measure of angle 3
(angle 3)+(angle 4) = 90
x+29 = 90
x = 90-29
x = 61
Angle 2 is congruent to angle 3 since triangle BEC is isosceles (BE = EC), so both angle 2 and angle 3 are 61 degrees each.
The rule says that:
each small angle has a small side
then the angle in front of BC is the smallest
in front of CA is the middle
in front of AB is the largest
I hope this helped and Good luck
thank you
F(x) = x4(x2 - 1)
f(-x) = (-x)4((-x)2 - 1)
f(-x) = x4(x2 - 1)
from above explanation it is clear that the function is even.
Let x=bob’s original amount of money
Let 9x=Bessy’s original amount of money
9x+4=5(x+4)
9x+4=5x+20
4x=16
x=4
9(4)=36
Bob had $4 before earning $4 and Bessy had $36 before earning $4
Answer: When the data given is spread across the graph at random in no certain order
Step-by-step explanation: