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andrew11 [14]
3 years ago
13

Jayden earns $54 every 9 days, based on this information how many day will it take for Jayden to earn $96

Mathematics
2 answers:
allsm [11]3 years ago
5 0

Answer:

It will take him 16 days

Step-by-step explanation:

If he gets $54 every 9 days then that means he get $6 a day. From that you can do 96/6 to get the answer. Hopefully that helps!

Aneli [31]3 years ago
5 0
He would get 6 dollars a day
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What should be done to solve the following equation?
Maslowich

The equation C -7 - 3/4 = 0 is an algebraic equation

To solve the equation we (a) add 7 and 3/4 to both sides of the equation

<h3>How to determine the action on the equation?</h3>

The equation is given as:

C -7 - 3/4 = 0

Make C the subject of formula by adding 7 and 3/4 to both sides of equation

C = 7 + 3/4

Now, we can solve for C

Hence, to solve the equation we (a) add 7 and 3/4 to both sides of the equation

Read more about equations at:

brainly.com/question/2972832

8 0
2 years ago
The attendance at a community block party was 3 children for every 2 adults. Which could be the number of children and adults at
kozerog [31]

Answer:

C

Step-by-step explanation:

If you divide the amount of children by 3 you get 82 then times in by 2 you get 264 which is the number of answers

3 0
2 years ago
3x-2(x+3)=4x-9-x is the question
kozerog [31]

Answer:

\large\boxed{x = 7}

Step-by-step explanation:

3x - 2(x + 3) = 4x - 9 - x

Start by multiplying 2 by the values in the parenthesis

3x - 2x + 6 = 4x - 9 - x

Subtract 3x - 2x and 4x - x

x + 5 = 3x - 9

Add 9 to both sides of the equation

x + 14 = 3x

Subtract x from both sides of the equation

14 = 2x

Divide both sides of the equation by 2

\large\boxed{x = 7}

Hope this helps :)

8 0
3 years ago
Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e
svet-max [94.6K]

ANSWER

y = 2x -4

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

x = 5 +  ln(t)

y =  {t}^{2}  + 5

From the first equation we make t the subject to get;

x - 5 =  ln(t)

t =  {e}^{x - 5}

We put it into the second equation.

y =  { ({e}^{x - 5}) }^{2}  + 5

y =  { ({e}^{2(x - 5)}) }  + 5

We differentiate to get;

\frac{dy}{dx}  = 2 {e}^{2(x - 5)}

At x=5,

\frac{dy}{dx}  = 2 {e}^{2(5 - 5)}

\frac{dy}{dx}  = 2 {e}^{0}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5)

y = 2x - 10 + 6

y = 2x -4

Without eliminating the parameter,

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

\frac{dy}{dx}  =  \frac{ 2t}{  \frac{1}{t} }

\frac{dy}{dx}  =  2 {t}^{2}

At x=5,

5 = 5 +  ln(t)

ln(t)  = 0

t =  {e}^{0}  = 1

This implies that,

\frac{dy}{dx}  =  2 {(1)}^{2}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5) =

y = 2x -4

5 0
3 years ago
What is the radius of a circle in which a 30 degrees arc is 2 inches long
igomit [66]

arc length = pi /180 * angle in degree * radius

2 = pi/180 * 30 *r

2 = pi/6 *r

multiply by 6/pi

12/pi =r

3.819718634 =r

Answer: r =3.82 inches


6 0
2 years ago
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