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Neko [114]
3 years ago
12

As an estimation we are told £3 is €4. Convert €32 to pounds. help pleaseeee!

Mathematics
1 answer:
ehidna [41]3 years ago
7 0
32 euros converts to 28.20 pounds
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Graph and solve the system <br><br> Y=-3x+3<br> Y=2x-7
guajiro [1.7K]
An equation of the form y=ax+b, where a and b are constants; y and x are variable, is called a linear equation.

They are called "linear" because if we draw all the solutions of such an equation, they form a line. 

This also means that it is enough to:
 
1. find to solutions 
2. plot them on the coordinate axis
3.join those 2 points

and all the solutions of the equation y=ax+b will be on that line.


Thus, to draw line y=-3x+3

let x=0, then y=3, so one solution is (0, 3)

let y=0, then x=1 so a second solution is (1, 0)

(remark we can pick x or y to be any value, then solve for the other)


to draw the second line y=2x-7

let x=0, then y=-7
let x=3, then y=-1


plot these points and join them as shown in the picture.


The solution of the system is the point where the lines intersect, which is
 (2, -3)


8 0
3 years ago
Read 2 more answers
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
PLEASEE GUYS HELP ME WITH THIS QUESTION IM STRUGGLING AND ITS DUE IN 14 MINS
ELEN [110]

use vanilla ice cream with that it's the best

8 0
2 years ago
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you have a photograph 12 in. wide and 18 in. long you surround the photograph with mat x in. wide you want to make a frame for t
BARSIC [14]
12:18=6:9=2:3
80÷5=16
16×2=32:16×3=48
32:48
3 0
3 years ago
If a football field is 100 yards. How long is 1 Million football feilds?
zlopas [31]
1,000,000 times 100 equals 100,000,000

Ok, this looks a lot harder than it is. Either way, a calculator/computer can work miracles. Have a good day!!
8 0
2 years ago
Read 2 more answers
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