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Mama L [17]
3 years ago
11

What is the product? StartFraction 4 k + 2 Over k squared minus 4 EndFraction times StartFraction k minus 2 Over 2 k + 1 EndFrac

tion StartFraction 4 Over 2 k + 1 EndFraction StartFraction 2 Over k minus 2 EndFraction StartFraction 2 Over 2 k + 1 EndFraction StartFraction 2 Over k + 2 EndFraction
Mathematics
2 answers:
Bas_tet [7]3 years ago
4 0

Answer:

\frac{2}{k+2}

Step-by-step explanation:

Given the expression:

\frac{4k+2}{k^2-4} * \frac{k-2}{2k+1}

We are to find the product as shown:

= \frac{4k+2}{k^2-4} * \frac{k-2}{2k+1}\\\\= \frac{2(2k+1)}{k^2-2^2} * \frac{k-2}{2k+1}\\\\= \frac{2(2k+1)}{(k-2)(k+2)} * \frac{k-2}{2k+1}\\\\=  \frac{2}{k+2} * 1\\\\= \frac{2}{k+2}

Hence the required function is \frac{2}{k+2}

Leni [432]3 years ago
4 0

d. <em>StartFraction 2 Over k + 2 EndFraction</em>

<em />

<em>aka</em>

<em />

d. <em>2/k+2</em>

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3 years ago
Need help with the left side
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Hope that helps!!!! :)


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