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vivado [14]
3 years ago
15

If m23 = 54°, find the measure of each missing angle.​

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

Holo nomelase ay pa la próxima

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Help please describe patterns as quick as possible thank you and have a great day
NARA [144]

Answer:

40,20,10

Step-by-step explanation:

3. 640÷2=320, 360÷2=160, 160÷2=80 and so on

4 0
2 years ago
What is the sum of the first five terms in the series 7+12+17+..?
nirvana33 [79]
7 + 12 + 17 + 22 + 27 = ( 7 + 27 ) + ( 12 + 22 ) + ( 34 / 2 ) = ( 34 / 1 ) + ( 34 / 1 ) + ( 34 / 2 ) = ( 68 / 2 ) + ( 68 / 2 ) + ( 34 / 2 ) = 170 / 2 = 85 .
3 0
3 years ago
The age of a father is three times that of his son. In ten year's time their ages will add up to 68 years. If the son is x years
Elodia [21]

Answer:

46 and 22

Step-by-step explanation:

let the father b (f) and d son is (s)

so

f=3s.....(1)

(f+10) +(s+10)=68 .... (2)

substitute f=3s in equation (2)

we have

(3s+10)+(s+10)=68

4s+20=68

4s=68-20

4s=48

s=12 .......(3)

substitute (3) in (1)

f=3*12

which f=36

in 10 year time

f+10 =46

s+10=22

3 0
2 years ago
Write the explicit formula for this geometric sequence.
Naily [24]

The explicit formula for this  geometric sequence 81, 27, 9, 3, … is aₙ = 81(1/3)ⁿ⁻¹. It has common ratio of 1/3 and first term of 81.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

A geometric sequence is in the form aₙ = ar⁽ⁿ⁻¹⁾, where a is the first term and r is the common ratio.

The geometric sequence 81, 27, 9, 3, … has common ratio:

r = 27/81 = 1/3

The explicit formula for this  geometric sequence 81, 27, 9, 3, … is aₙ = 81(1/3)ⁿ⁻¹. It has common ratio of 1/3 and first term of 81.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

7 0
2 years ago
Which congruence criteria can be used directly from the information about triangles HIJ and MNO to prove IJ¯¯¯¯¯¯≅MN¯¯¯¯¯¯¯¯¯¯ b
skelet666 [1.2K]

Answer: \overline{IJ}\cong \overline{MN}

Step-by-step explanation:

Given: In triangle HIJ and triangle MNO we have

\overline{HI}\cong \overline{NO}, \angle{I}\cong \angle{N} ,\angle{H}\cong \angle{O}

here, HI and NN are the included side between  ∠I & ∠H and ∠N and ∠O.

So , by ASA congruence rule,

ΔHIJ ≅ ΔMNO

So by CPCTC  (corresponding parts of the congruent triangles are congruent)

\overline{IJ}\cong \overline{MN}

7 0
2 years ago
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