2 years ago

Determine the initial value

1 answer:

6 0

Hey there I am just telling you , it seems that your questions is incomplete . Can you kindly post the whole question then I am able to solve it.

please don't mind.

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Line N

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2 years ago

Solve for X. <br><br> <img src="https://tex.z-dn.net/?f=log_%7B8%7D%20x-log_%7B8%7D%20%28-2x%2B4%29%20%3D%20log_%7B8%7D%203" id=

taurus [48]

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Step-by-step explanation:

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Then,simplifying:

$log_{8}(\frac{x}{-2x+4}) = log_{8}(3)$

Apply base 8 to boths sides and then solve for "x":

$8^{log_{8}(\frac{x}{-2x+4})}=8^{log_{8}(3)}\\\\\frac{x}{-2x+4}=3\\\\x=3(-2x+4)\\\\x=-6x+12\\x+6x=12\\7x=12\\\\x=\frac{12}{7}$

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