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Amiraneli [1.4K]
3 years ago
7

PLEASE ANSWER ASAP

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0

Answer:

A. Blue

C. Green

There are thirty total marbles. 1/5 of 30 is 6. Both these colors have six marbles.

torisob [31]3 years ago
3 0

Answer:

i don't really know but I would say 4 and one of the 6's

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Type the correct answer in each box. If necessary, use / for the fraction bar(s). In this triangle, the product of sin B and tan
Alenkinab [10]

Answer:

sinB  is eaual to tanC

Step-by-step explanation:

what ever you get for sinB, tanC will always be equal to it

6 0
3 years ago
Please someone answer for this question
Maslowich
First one is 5/3
Second one is: 5
Third one is: 15
3 0
3 years ago
Read 2 more answers
What are the solutions of the inequality? Graph the solutions. b – 4 > 4 Question 12 options: b > –8 b < –8 b > 8 b
12345 [234]

Hello there! :)

Answer:

\boxed{b>8}\checkmark

<h2><u><em>*****The answer should have a GREATER THAN SIGN AND POSITIVE TOO!*****</em></u></h2>

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

PEMDAS

Order of operations

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

Left/Right

First, you add by 4 from both sides of an equation.

b-4+4>4+4

Then, you add numbers from left/right.

4+4=8

\boxed{b>8}, which is our final answer.

Hope this helps you!

Have a nice day! :)

:D

-Charlie

Thank you so much! :)

6 0
3 years ago
Two numbers rolled can be added to get a sum. Find P(sum is even.)
azamat
When you roll two numbers you have four kinds of outcomes: EE, EO, OE, OO (where E = even, O = odd).

You get an even sum only if you sum two numbers that are both even or both odd, therefore the outcomes wanted are two: EE and OO.

Therefore:
P(sum is even) = 2 / 4 = 0.5

Hence, there is a 50% probability that, when you roll two numbers, their sum will be even.
6 0
3 years ago
If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro
yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

\Rightarrow f(x) = 2\cos x + e^{2x}

\Rightarrow f'(x) = -2\sin x + 2e^{2x}

And,

\Rightarrow f(2) = 2\cos 2 + e^{4}

\Rightarrow f'(2) = -2\sin 2 + 2e^{4}

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

\Rightarrow y-y_1=m(x-x_1)

\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)

\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})

The value of f(2.1) will be

\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})

\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})

\Rightarrow y=64.5946

According to given function, f(2.1) will be,

\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}

\Rightarrow f(2.1) = 65.6766

\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%

5 0
3 years ago
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