Ask question

Ask question

All categories

3 years ago

11

A car dealership pays $8,550 for a car. They markup the price by 20.4% to get the retail price. What is the retail price of the

car at this dealership? *

1 answer:

DochEvi [55]3 years ago

4 0

Answer:

$9802.90

Step-by-step explanation:

$9802.90

Step-by-step explanation:

17.4% = 0.174

So retail price = 8,350 + 8,350 * 0.174

= $9802.90

You might be interested in

X/x-3 times x-1/3-x

Tema [17]

X-X^2/ (x-3)^2 try that I’m not 100% sure tho

8 0

3 years ago

How does the speaker’s repetition of the neighbor’s cherished belief about the importance of walls (lines 27 and 45) convey the

Reptile [31]

Answer:

C The speaker describes the neighbor’s superstitious beliefs about elves in order to characterize him as uncivilized and misguided. The speaker describes the neighbor’s superstitious beliefs about elves in order to characterize him as uncivilized and misguided.

Step-by-step explanation:

This is likely the answer to the question asked.

6 0

3 years ago

Please help! I was absent!

lesya692 [45]

I got 6.3 not sure if Im right

7 0

3 years ago

A recent study suggests that men are more likely to go to a social media channel to compare prices of products than women at a r

murzikaleks [220]

Answer:

just graph it 6 women to 5 men so put that on a graph?

Step-by-step explanation:

3 0

3 years ago

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0

4 years ago