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3 years ago

Slope=1/2;(-2,7) Equation:

Mathematics

2 answers:

ivanzaharov [21]3 years ago

6 0

y= 1/2x + 7 -> slope intercept form

romanna [79]3 years ago

4 0

Point slope form:
(y-y1) = m (x-x1)

m=slope=1/2
given point (x1,y1) = (-2,7)

(y-7) = 1/2 (x+2)

slope intercept form:

y-7 = 1/2x + 1
y = 1/2x + 8

ANSWER: y=1/2x + 8

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Quiz! 2x + 2 = 4 find x!

lilavasa [31]

<h3>Solution</h3>

2x + 2 = 4
2x = 4 - 2
2x = 2
x = 2 ÷ 2
x = 1

<h3>Proof</h3>

2(1) + 2
= 2 + 2
= 4

7 0

3 years ago

Read 2 more answers

Ed is 7 years older than ted. eds age is also 3 over 2 times teds age. how old are ed and ted

Katyanochek1 [597]

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3 years ago

A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3

AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

$x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km$

Now, we can find the time when the trains will be 1520 km apart:

$1520 km = (x_{1} + 240 km) + x_{2}$

Where 1 is for the cargo train and 2 is for the passenger train.

$1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}$

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

$1520 km = (v_{1}*t + 240 km) + v_{2}t$

$t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h$

For the cargo train, it will be 1520 km apart from the passenger train at:

$t_{1} = 12 pm + 2 h + 40 min = 2:40 pm$

And for a passenger train, it will be 1520 km apart from the cargo train at:

$t_{2} = 2 pm + 2 h + 40 min = 4:40 pm$

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) The distance traveled by both trains is given by:

$x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km$

$x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km$

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!

5 0

3 years ago

The length of a rectangle is 3 more than 3 times its width. The perimeter of the rectangle is 174 inches. What is the length of

saveliy_v [14]

Answer:

l = w + 3cm

l = w + 3cmp = 2l + 2w = 58cm

l = w + 3cmp = 2l + 2w = 58cm 

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm

l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:

I hope this helps you.

5 0

3 years ago

In ΔRST, the measure of ∠T=90°, the measure of ∠R=67°, and TR = 94 feet. Find the length of RS to the nearest tenth of a foot.

Dimas [21]

Answer:

the length of RS to the nearest tenth of a foot is 240.6ft

3 0

3 years ago