Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
Answer:
X=8
Step-by-step explanation:
Opposite side angles on the transversal are congruent.
SO 6x-2=46
46+2=48
48/6=8
X=8
Answer:
is thier any way you can take a picture of what the problem is cause alot of the equation are not adding up the way you put them
Answer:
A I believe
Step-by-step explanation:
