Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has

and

.
Since O lies in second quadrant

and

.
Answer:
.
To find the area of his exclusion zone you would need to understand that a triangle with dimensions of 3, 4, and 5 represent a right triangle.
This means the exclusion zone would be applied to the base and the height of the triangular space.
You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.
Please see the attached picture to understand this.
You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.
(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².
The exclusion space is 9 km².
Answer:
the slope of the line in the graph is: 3
the y-intercept is: -4
the equation of the line is: y=3x-4
Step-by-step explanation:
If we find a point on the graph and count it until it reaches other solid point we get that you have to go up three and to the right by one. This solid point I looked at was (0,-4) and counted up to (-1,1). To find the slope, we have to simply count and use "rise over run". The rise is 3 for every 1 we run, making the slope 3/1 which is 3.
the y-intercept is the point on the graph that touches the y-axis on the graph. The only point on the graph that touches the y-axis is -4, making the y-intercept -4.
The equation for a graph is y=mx+b. m would be the slope and b would be the y-intercept. We know that the slope is 3 (m) and that the y-intercept is -4 (b). Putting them together, we get that the equation of the graph is y=3x-4.
Move all terms to one side
4w^2 + 49 + 28w = 0
Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7
(2w)^2 + 2(2w)(7) + 7^2 = 0
Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2
(2w + 7)^2 = 0
Take the square root of both sides
3w + 7 = 0
Subtract 7 from both sides
2w = -7
Divide both sides by 2
<u>w = -7/2</u>
Answer:
Step-by-step explanation:
sum of angles of parallelogram=360 degrees
adjacent angles add up to 180 degrees (supplementary angles)
Angle A=104 (DAB=104)
Angle D=180-104=76 degrees (angle ADB)
Angle B=60 degrees
Angle C=180-60=120 (DCB)