Answer:
x = 7![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
Step-by-step explanation:
Answer:
What grade is this???
Step-by-step explanation:
Answer:
![=20x^4-36x^3+47x^2-13x+66](https://tex.z-dn.net/?f=%3D20x%5E4-36x%5E3%2B47x%5E2-13x%2B66)
Step-by-step explanation:
![\left(10x^2+7x+11\right)\left(2x^2-5x+6\right)\\=10x^2\cdot \:2x^2+10x^2\left(-5x\right)+10x^2\cdot \:6+7x\cdot \:2x^2+7x\left(-5x\right)+7x\cdot \:6+11\cdot \:2x^2+11\left(-5x\right)+11\cdot \:6\\\mathrm{Apply\:minus-plus\:rules}\\+\left(-a\right)=-a\\=10\cdot \:2x^2x^2-10\cdot \:5x^2x+10\cdot \:6x^2+7\cdot \:2x^2x-7\cdot \:5xx+7\cdot \:6x+11\cdot \:2x^2-11\cdot \:5x+11\cdot \:6\\=20x^4-50x^3+60x^2+14x^3-35x^2+42x+22x^2-55x+66\\=20x^4-50x^3+14x^3+60x^2-35x^2+22x^2+42x-55x+66\\](https://tex.z-dn.net/?f=%5Cleft%2810x%5E2%2B7x%2B11%5Cright%29%5Cleft%282x%5E2-5x%2B6%5Cright%29%5C%5C%3D10x%5E2%5Ccdot%20%5C%3A2x%5E2%2B10x%5E2%5Cleft%28-5x%5Cright%29%2B10x%5E2%5Ccdot%20%5C%3A6%2B7x%5Ccdot%20%5C%3A2x%5E2%2B7x%5Cleft%28-5x%5Cright%29%2B7x%5Ccdot%20%5C%3A6%2B11%5Ccdot%20%5C%3A2x%5E2%2B11%5Cleft%28-5x%5Cright%29%2B11%5Ccdot%20%5C%3A6%5C%5C%5Cmathrm%7BApply%5C%3Aminus-plus%5C%3Arules%7D%5C%5C%2B%5Cleft%28-a%5Cright%29%3D-a%5C%5C%3D10%5Ccdot%20%5C%3A2x%5E2x%5E2-10%5Ccdot%20%5C%3A5x%5E2x%2B10%5Ccdot%20%5C%3A6x%5E2%2B7%5Ccdot%20%5C%3A2x%5E2x-7%5Ccdot%20%5C%3A5xx%2B7%5Ccdot%20%5C%3A6x%2B11%5Ccdot%20%5C%3A2x%5E2-11%5Ccdot%20%5C%3A5x%2B11%5Ccdot%20%5C%3A6%5C%5C%3D20x%5E4-50x%5E3%2B60x%5E2%2B14x%5E3-35x%5E2%2B42x%2B22x%5E2-55x%2B66%5C%5C%3D20x%5E4-50x%5E3%2B14x%5E3%2B60x%5E2-35x%5E2%2B22x%5E2%2B42x-55x%2B66%5C%5C)
![\mathrm{Add\:similar\:elements:}\:60x^2-35x^2+22x^2=47x^2\\=20x^4-50x^3+14x^3+47x^2+42x-55x+66\\\mathrm{Add\:similar\:elements:}\:-50x^3+14x^3=-36x^3\\=20x^4-36x^3+47x^2+42x-55x+66\\\mathrm{Add\:similar\:elements:}\:42x-55x=-13x\\=20x^4-36x^3+47x^2-13x+66](https://tex.z-dn.net/?f=%5Cmathrm%7BAdd%5C%3Asimilar%5C%3Aelements%3A%7D%5C%3A60x%5E2-35x%5E2%2B22x%5E2%3D47x%5E2%5C%5C%3D20x%5E4-50x%5E3%2B14x%5E3%2B47x%5E2%2B42x-55x%2B66%5C%5C%5Cmathrm%7BAdd%5C%3Asimilar%5C%3Aelements%3A%7D%5C%3A-50x%5E3%2B14x%5E3%3D-36x%5E3%5C%5C%3D20x%5E4-36x%5E3%2B47x%5E2%2B42x-55x%2B66%5C%5C%5Cmathrm%7BAdd%5C%3Asimilar%5C%3Aelements%3A%7D%5C%3A42x-55x%3D-13x%5C%5C%3D20x%5E4-36x%5E3%2B47x%5E2-13x%2B66)
Answer:
The answer is 154.8 ml
Step-by-step explanation:
In this question, the amount of pure acid is 18% of the total solution, that is, 18% of 860 milliliters. So
0.18*860 = 154.8 ml
The answer is 154.8 ml
The solutions to the problem are 2 and -5.
<h2>Given to us</h2>
![12^{x^2+5x-4}= 12^{2x+6}](https://tex.z-dn.net/?f=12%5E%7Bx%5E2%2B5x-4%7D%3D%2012%5E%7B2x%2B6%7D)
<h2>To find</h2>
the value of x.
<h3>Solution</h3>
![12^{x^2+5x-4}= 12^{2x+6}](https://tex.z-dn.net/?f=12%5E%7Bx%5E2%2B5x-4%7D%3D%2012%5E%7B2x%2B6%7D)
as the base on both, the sides are the same, therefore, equating the powers to each other.
![{x^2+5x-4}= {2x+6}\\x^2 + 5x-2x-4-6=0\\x^2 + 5x-2x-10=0\\x(x+5)-2(x+5)=0\\(x-2)(x+5) = 0\\](https://tex.z-dn.net/?f=%7Bx%5E2%2B5x-4%7D%3D%20%7B2x%2B6%7D%5C%5Cx%5E2%20%2B%205x-2x-4-6%3D0%5C%5Cx%5E2%20%2B%205x-2x-10%3D0%5C%5Cx%28x%2B5%29-2%28x%2B5%29%3D0%5C%5C%28x-2%29%28x%2B5%29%20%3D%200%5C%5C)
we got the two factors.
Now equating both the factors against 0,
![(x-2) =0\\x=2](https://tex.z-dn.net/?f=%28x-2%29%20%3D0%5C%5Cx%3D2)
![(x+5)=0\\x=-5](https://tex.z-dn.net/?f=%28x%2B5%29%3D0%5C%5Cx%3D-5)
Therefore, the solutions to the problem are 2 and -5.
Learn more about factorization:
brainly.com/question/20293447?referrer=searchResults