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Alborosie
3 years ago
6

Solve: 12 Superscript x squared 5 x minus 4 Baseline = 12 Superscript 2 x 6 x = 2 x = –5 x = 2, x = –5 no solution.

Mathematics
1 answer:
Llana [10]3 years ago
8 0

The solutions to the problem are 2 and -5.

<h2>Given to us</h2>

12^{x^2+5x-4}= 12^{2x+6}

<h2>To find</h2>

the value of x.

<h3>Solution</h3>

12^{x^2+5x-4}= 12^{2x+6}

as the base on both, the sides are the same, therefore, equating the powers to each other.

{x^2+5x-4}= {2x+6}\\x^2 + 5x-2x-4-6=0\\x^2 + 5x-2x-10=0\\x(x+5)-2(x+5)=0\\(x-2)(x+5) = 0\\

we got the two factors.

Now equating both the factors against 0,

(x-2) =0\\x=2

(x+5)=0\\x=-5

Therefore, the solutions to the problem are 2 and -5.

Learn more about factorization:

brainly.com/question/20293447?referrer=searchResults

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