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ki77a [65]
3 years ago
12

Drop your snap if I can talk to you about a seventh grade math test on circumference and angles?

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
5 0

Answer:

nikespear

Step-by-step explanation:

Natali5045456 [20]3 years ago
5 0
I’m in high school oop
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2ln(5x)=8 solve for x
White raven [17]
lnx=log_ex\\----------\\log_ab=c\iff a^c=b\\----------\\Domain:\\5x > 0\ \ \ |divide\ both\ sides\ by\ 5\\x > 0\\D:x\in\mathbb{R^+}\\----------------------\\2ln(5x)=8\ \ \ \ |divide\ both\ sides\ by\ 2\\\\ln(5x)=4\iff e^4=5x\\\\5x=e^4\ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{x=\frac{e^4}{5}\in D}
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3 years ago
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How would I solve y-8+3(y+4)
konstantin123 [22]

Answer:

y-8+3y+12

4y+4

Step-by-step explanation:

y-8+3y+12

4y+4 is your answer

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3 years ago
Plss help ! I will give you brainliest
Lady_Fox [76]

Answer:

16 + -16 -4 ( 20 ) - 6)

Step-by-step explanation:

here is answer

8 0
3 years ago
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What is the value of this numeric expression:<br> 19 x 10 to the power of 2<br> Thank u!
ElenaW [278]

Answer: 36100

Step-by-step explanation:

19x10

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3 0
1 year ago
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Given △GHI and △JKL, GI = 5, HI = 4, JK = 4, and JL = 5, what else do you need to know to prove the two triangles are congruent
blsea [12.9K]

Answer:

△ GHI ≅ △ JKL. (Proved)

Step-by-step explanation:

In triangle Δ GHI, GI = 5 and HI = 4.

If we consider the triangle is a right triangle having hypotenuse = 5 and any other leg = 4.

Then this will follow the Pythagoras theorem as 3² + 4² = 5², where 3 is the other leg.

Therefore, Δ GHI is a right triangle having hypotenuse 5 and one leg 4.

Similarly, we can prove that △ JKL is also a right triangle(Since JK = 4 and  JL = 5), having hypotenuse 5 and one leg 4.

Therefore, applying HL rule, we cam conclude △ GHI ≅ △ JKL. (Proved)

7 0
3 years ago
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