7(7a-9)>84
first multiple out to get rid of the parentheses
49a - 63 > 84
add 63 to both sides
49a > 147
Divide by 49 and flip the sign because when you divide a inequality you have to flip the sign
a < 3
Answer:
(sqrt(7))/3 or decimal 0.8819171036881968635005385845464201419034197276941500601227781530...
Step-by-step explanation:
Simplify the following:
(sqrt(14))/(sqrt(18))
Hint: | Simplify radicals.
sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):
(sqrt(14))/(3 sqrt(2))
Hint: | Multiply numerator and denominator of (sqrt(14))/(3 sqrt(2)) by sqrt(2).
Rationalize the denominator. (sqrt(14))/(3 sqrt(2)) = (sqrt(14))/(3 sqrt(2))×(sqrt(2))/(sqrt(2)) = (sqrt(14) sqrt(2))/(3×2):
(sqrt(14) sqrt(2))/(3×2)
Hint: | Multiply 3 and 2 together.
3×2 = 6:
(sqrt(14) sqrt(2))/6
Hint: | For a>=0, sqrt(a) sqrt(b) = sqrt(a b). Apply this to sqrt(14) sqrt(2).
sqrt(14) sqrt(2) = sqrt(14×2):
(sqrt(14×2))/6
Hint: | Multiply 14 and 2 together.
14×2 = 28:
(sqrt(28))/6
Hint: | Simplify radicals.
sqrt(28) = sqrt(2^2×7) = 2 sqrt(7):
(2 sqrt(7))/6
Hint: | In (2 sqrt(7))/6, divide 6 in the denominator by 2 in the numerator.
2/6 = 2/(2×3) = 1/3:
Answer: (sqrt(7))/3
<span>In the question "for the place values that occur to the right of the decimal point, each place value is ten times ____ than the place value to its left"
The correct answer is smaller because in the place value system, the place values to the left of the decimal point decreases by a factor of ten for every number to the right.
Thus, each new number is ten times smaller than the number to its left.</span>
Answer:
see below
Step-by-step explanation:
I enter the equation into a graphing calculator and let it do the graphing.
___
If you're graphing this by hand, you start by looking for the parent function. Here, it is |x|. That has a vertex of (0, 0) and a slope of +1 to the right of the vertex and a slope of -1 to the left of the vertex.
Here, the function is multiplied by -3/2, so will open downward and have slopes of magnitude 3/2 (not 1). The graph has been translated 5 units upward, so the vertex is (0, 5).
I'd start by plotting the vertex point at (0, 5), then identifying points with slope ±3/2 either side of it. To the left, it is left 2 and down 3 to (-2, 2). The points on the right of the vertex are symmetrically located about the y-axis, so one of them will be (2, 2).
Of course, you don't plot any function values for x > 4.
Answer:
I'm not so sure that it does
Step-by-step explanation:
