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3 years ago

Allowing 3 feet for the door ,how much baseboard wen john need to enclose a square room where each wall measures feet ?

Mathematics

1 answer:

Dimas [21]3 years ago

3 0

11x11=121

You have to minus the 3 feet of the door = 118

Hope this helps.

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Determine the quotient, g(x), and remainder, r(x) when

lianna [129]

Answer:

Quotient : 2x^2 + 5x + 3

Remainder : x + 3

Step-by-step explanation:

I've attached the solution

5 0

2 years ago

F(x) = x^2+x-2/x^2-3x-4

Andrej [43]

i. Domain and Range

The given function is

$f(x)=\frac{x^2+x-2}{x^2-3x-4}$

The domain of this function is,

$x^2-3x-4\ne 0$

$(x-4)(x+1)\ne 0$

$x\ne4,xne -1$

The range refers to the y-values for which x is defined. x is defined for all values of y.

The range is all real numbers. See graph

ii. x-and-y-intercept

For x- intercept intercept we put $f(x)=0$

This implies that;

$\frac{x^2+x-2}{x^2-3x-4}=0$

This will give us

$x^2+x-2=0$

$\Rightarrow x^2+x-2=0$

$\Rightarrow x^2+2x--x-2=0$

$\Rightarrow x(x+2)-1(x+2)=0$

$\Rightarrow (x+2)(x-1)=0$

$\Rightarrow (x+2)=0,(x-1)=0$

$\Rightarrow x=-2,x=1$

The x-intercepts are $(-2,0),(1,0)$

For y-intercept, we put

$x=0$ to obtain;

$f(0)=\frac{0^2+0-2}{0^2-3(0)-4}$

$f(0)=\frac{1}{2}$

The y-intercept is

$(0,\frac{1}{2})$

iii. Horizontal asyptote

Since degree of the numerator and the denominator are the same, there is a horizontal asymptote

To find the horizontal asymptote.

We divide the leading coefficient of the numerator by the leading coefficient of the denominator.

The horizontal asymptote is $y=\frac{1}{1}=1$

iv. Vertical asymptote

To find the vertical asymptote, we equate the denominator to zero to get;

$x^2-3x-4=0$

This implies that;

$x^2+x-4x-4=0$

Split the middle term

$x(x+1)-4(x+1)=0$

Factor

$(x+1)(x-4)=0$

Factor further

$(x+1)=0,(x-4)=0$

$x=-1,x=4$

The vertical asymptotes are $x=-1,x=4$

8 0

2 years ago

Read 2 more answers

What is the solution of the system?

Darya [45]

The solution is 0,3 I put those answers into the equation, comment on this answer if you want me to explain.

8 0

3 years ago

Read 2 more answers

Difference quotient

Nina [5.8K]

$f(x)=5x^2-5x-6
\\ \quad \\

\begin{cases}
f(\boxed{x+h})=5(\boxed{x+h})^2-5(\boxed{x+h})-6
\end{cases}\qquad thus
\\ \quad \\
\cfrac{f(x+h)-f(x)}{h}\qquad \textit{will be then}
\\ \quad \\
\cfrac{[5({x+h})^2-5({x+h})-6]\quad -\quad [5x^2-5x-6]}{h}
\\ \quad \\
\cfrac{[5(x^2+2xh+h^2)-5(x+h)-6]-[5x^2-5x-6]}{h}
$

$\cfrac{\underline{5x^2}+10xh+5h^2\underline{-5x}-5h\underline{-6}\underline{-5x^2}\underline{+5x}\underline{+6}}{h}\impliedby \textit{canceling those ones}
\\ \quad \\
\cfrac{10xh+5h^2-5h}{h}\impliedby \textit{common factor}
\\ \quad \\
\cfrac{5\underline{h}(2x+h-1)}{\underline{h}}$

and surely, you'd know what that is

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3 years ago

How much mm is 32 degrees?

N76 [4]

Answer:

558.5053606381886

Step-by-step explanation:

32 × 17.453292519943

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1 year ago