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andrey2020 [161]
3 years ago
9

Federico has $36 to spend on clothes. He wants to buy a shirt for $8 and the rest on pants that are on sale for $10 a pair. Whic

h inequality could he use to determine the number of pairs of pants he can buy?
Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer: you can buy 2 pairs of pants 1 pair of a shirt and have 2 dollars left

Step-by-step explanation:The two pairs of pants in buys the money with are $20

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2(48)+2(8w)+2(6w)=208 please explain
babymother [125]

Answer:

w=4

Step-by-step explanation:

2(48)+2(8w)+2(6w)=208

1) Start by Distributing the value outside of the parenthesis:

96+16w+12w=208

2) Combine alike terms:

96+28w=208

3) Subtract 96 from both sides:

28w=112

4)Divide both sides by 28 to isolate w:

w=4

Let me know if you do not understand :)

4 0
3 years ago
Let $z$ be a complex number such that $z^5 = 1$ and $z \neq 1.$ Compute
snow_lady [41]

Answer:

The answer is 4

Step-by-step explanation: i did it

5 0
2 years ago
Rita is saving up 15,000 to put a down payment on a condominium. If he starts with 8,000 saved and saves an additional $850 each
belka [17]
I think there is more to the question, but the equation to solve for the number of months until Rita has enough money to put a down payment for a condominium is 15,000=8,000+850X
3 0
3 years ago
A cone and its dimensions are shown in the diagram. Which measurement is closest to the volume of the cone in cubic inches?
Diano4ka-milaya [45]
20 Cubic Inches^3.

Explanation:

The volume of a cone is Pi*R^2*H*1/3

We know the height, but we are given the diameter instead of radius. So divide 5.625 by 2. You get 2.8125.

Plug everything into the formula.

Pi*2.8125^2*7.5*1/3

(The ^2 means squared, or to the second power)

You get a number close to 20. Since we don’t know Pi, and we are not given a substitute for Pi, we make the answer in terms of Pi.

20 Cubic Inches^3.

Also, people who don’t know the answers to questions shouldn’t just put a random answer for the points. It’s unfair.


3 0
3 years ago
two hundred tickets for the school play were sold. tickets cost $2 for students and $3 for adults. the total amount collected wa
Gre4nikov [31]
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
4 0
3 years ago
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