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andrey2020 [161]
3 years ago
9

Federico has $36 to spend on clothes. He wants to buy a shirt for $8 and the rest on pants that are on sale for $10 a pair. Whic

h inequality could he use to determine the number of pairs of pants he can buy?
Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer: you can buy 2 pairs of pants 1 pair of a shirt and have 2 dollars left

Step-by-step explanation:The two pairs of pants in buys the money with are $20

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At an art exhibition there are 12 paintings of which 10 are original. A visitor selects a painting at random and before decides
Reika [66]

Answer:

a) 0.8333

b) 0.75

c) 0.8181 or 0.9090

Step-by-step explanation:

a)

The probability the visitor selects an authentic painting is  

10/12 = 0.8333

b)

Since the opinion of the expert does not depend on your choice, the events are <em>independent</em>, so the probability that the expert says is authentic and it really is, is

0.8333*0.9 = 0.75

c)

If the expert decides the painting is a copy and it is not, then there are 11 paintings of which 9 are authentic, so the probability the visitor selects a new original painting is

9/11= 0.8181

If the expert decides the painting is a copy and it is, then there are 11 paintings of which 10 are authentic, so the probability the visitor selects a new original painting is

10/11= 0.9090

8 0
3 years ago
If RT = 6 and RS = 9, then RX =<br> A - sqrt(54)<br> B - 13.5<br> C - 7.2<br> D - 4
wolverine [178]

Answer:

Option D RX=4 units

Step-by-step explanation:

we know that

<em>In the right triangle RTS</em>

The cosine of angle TRS is equal to

cos(TRS)=RT/RS

substitute

cos(TRS)=6/9 -----> equation A

<em>In the right triangle RTX</em>

The cosine of angle TRX is equal to

cos(TRX)=RX/RT

substitute

cos(TRX)=RX/6 -----> equation B

∠TRS=∠TRX -----> is the same angle

Match equation A and equation B

6/9=RX/6

RX=6*6/9=4 units

5 0
3 years ago
Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
5/16 as a decimal..?
madam [21]

Answer:

0.3125

Step-by-step explanation:

type that into a calculator

7 0
2 years ago
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A mathematician works for t hours per day and solves p problems per hour, where t and p are positive integers and 1
Crazy boy [7]

Answer:

what's the question?

Step-by-step explanation:

6 0
2 years ago
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