I need help with 14 and 15 help a friend out pls

Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company

erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that $n = 16$

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that $p = 0.5$

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0$

$P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002$

$P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018$

$P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105$

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0

3 years ago

HELP ASAP

astra-53 [7]

Answer:

Step-by-step explanation:

We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2

x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2

A = 3.14 * (5)^2

A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h

A = 1/2 *6 * 5

A = 15 cm^2

Atriangles = 2 * 15

Atriangles = 30 cm^2

Ashaded = 25pi - 30

8 0

2 years ago

20 POINTS / WILL GIVE BRAINLIEST

padilas [110]

Answer: Total Volume = 15π + 18 π= 33π cubic mm

Step-by-step explanation:

What is the volume of the composite figure? Leave the answer in terms of π.

_33π mm3

We have a cone here conjoined to a semi-sphere.

so

Cone volume: C = (1/3)*(πr^2) * h

semi-sphere volume : V = (1/2)* (4/3) * (π * r^3)

r = 3 mm and h = 5mm

so C = (1/3)*(π (3)^2) * 5 = 15π cubic mm

V = (1/2)* (4/3) * (π * 3^3) = 18 π cubic mm

Total Volume = 15π + 18 π= 33π cubic mm

3 0

3 years ago

M^2+m-90 please explain steps to factor

tangare [24]

If you use photomath it will give you the answer and the steps to solve its a great app.

3 0

3 years ago

Factorise fully 28y2 – 24y

Fittoniya [83]

Answer:

4y(7y - 6)

Step-by-step explanation:

4 0

2 years ago