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Alecsey [184]
3 years ago
15

The collection of all possible events is called A. a simple probability. B. a sample space. C. a joint probability. D. the null

set.
Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

B. a sample space

Step-by-step explanation:

Sample space is considered as the set of all possible outcomes of a randomized experiment.

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If using the method of completing the square to solve the quadratic equation x^2 + 9 x + 7 = 0 , which number would have to be a
FinnZ [79.3K]

Answer:

(x+9)^2=53/4

Step-by-step explanation:

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What is ...1000.0000..000000km x 3,000?
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4

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duh

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2 years ago
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Factor 16y^2 + 12y completely.
Luden [163]
16y²+12y = 4y(4y+3)

D. 4y(4y + 3)
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I need help with this question so hard
qaws [65]

Answer:

The answer to part B will be for length the mean is 2.08, the median is 2.6, and the mode is 2.6. For height the mean is 1.5, the median is 1.4, and there isn't a mode since no number repeat. It will the 0.6, 1.0, 1.4, 1.7, 2.8. Hope this helps!

Step-by-step explanation:

3 0
2 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
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