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SVEN [57.7K]
3 years ago
5

Millieters in square

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Mathematics
1 answer:
DochEvi [55]3 years ago
7 0

Answer:

sorry I don´t know

Step-by-step explanation:

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In 1983, a hardcover dictionary cost $145.75. If the CPI is currently 209, what would a hardcover dictionary cost today? Round t
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(8 1/3) ^2 = 4 x <br><br> x =
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x = 729/4 = 182.250

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The net of a rectangular prism is shown.
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The U.S. Department of Agriculture records data on farm acreage and number of farms by county for every county in the country. T
lisabon 2012 [21]

Solution :

From the table,

Number of countries = $N_i$

Mean = $\overline Y_i$

Standard deviation = $\sigma_i$

Margin of error of B = 50,000 acres

So we determine the $\text{sample size n}$ and then allocate the four regions of $n_1, n_2, n_3$ and $n_4$.

Under the $\text{proportional allocation}$, the $\text{equation}$ for the value of $n_1$ which yields $V(\overline Y_{st}) = D = \frac{B^2}{H}$  is given by :

$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$

Let us complete the numerator

$\sum_{K=1}^L N_K \sigma^2_K = N_1\sigma_1^2 + N_2\sigma_2^2 + N_3\sigma_3^2 + N_4\sigma_4^2$

                $= 1052 \times (271)^2 +  210 \times (79)^2 + 1376 \times (244)^2 + 418 \times (837)^2 $

                = 453329920

The bound on the error of estimation is B = 50,000 acres

Hence we get

$D=\frac{B^2}{H}$

  $=\frac{50000^2}{4}$

  = 625,000,000

$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$

  $=\frac{453329920}{3056 \times 625 + \frac{1}{3056} \times 453329920}$

 = 220.24044

≈ 221 (approximately)

Therefore, the sample size under the proportional allocation from each stratum are given by :

$n_1=n\left[\frac{N_1}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{1052}{3056}\right]$

   ≈ 76

$n_2=n\left[\frac{N_2}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{210}{3056}\right]$

   ≈ 15

$n_3=n\left[\frac{N_3}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{1376}{3056}\right]$

   ≈ 100

$n_4=n\left[\frac{N_4}{\sum_{K=1}^\mu N_K}\right]$

   $=221\left[\frac{418}{3056}\right]$

   ≈ 30

Thus, we should select 76 counties from North central region, 15 counties from the north east region, 100 from south region and 30 from west region.

We can also estimate mean acreage of each county across all the county with a margin of error of 50,000 acres.

8 0
3 years ago
(3^2+4−2)(2^2−3−4) can you guys please solve this for me please.
Degger [83]

Answer:

-33

Step-by-step explanation:

(3^2+4-2)(2^2-3-4)

(9+4-2)(4-3-4)

(13-2)(1-4)

(11) · (-3)

(-33)

6 0
3 years ago
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