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Katen [24]
3 years ago
9

According to the weather report, what is the chance of rain or snow?

Mathematics
2 answers:
Viefleur [7K]3 years ago
5 0

Answer:

50? or together will be 90?

ArbitrLikvidat [17]3 years ago
3 0
Just add the two ratios 48+42=90%

Hope you get it :)
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Help me plsssss?!?!?!????!!
telo118 [61]

Answer: quit

Step-by-step explanation:

8 0
2 years ago
Which triangle has hypotenuse Side B F? A cube. The top face has points G, B, C, F and the bottom face has points H, A, D, E. tr
jolli1 [7]

Answer:

ΔBFG

Step-by-step explanation:

Since top face points are

  • G, B, C and F

and bottom face points are

  • H, A, D and E

The side BF can be a hypotenuse of the triangle BFG only

This triangle is on the top face and all the rest given triangles are formed by the points that are not on the same face, therefore BF can't be a hypotenuse of those, as ether B or F is becoming a right angle of the triangles.

3 0
3 years ago
Solve equation a+6a-9=30
ra1l [238]
A=5 4/7 or 5.57142857143 
I cannot be simplified any more
8 0
3 years ago
Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
3 years ago
Solve for x <br> x-31=-90<br><br> show how you got the answer
Vinil7 [7]

Answer:

x= -59

Step-by-step explanation:

x-31=-90

Adding 31 to both sides we get

x-31+31=-90+31

x=-59

4 0
3 years ago
Read 2 more answers
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