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hodyreva [135]
3 years ago
7

Lin and Diego both ran for 10 seconds, each at their own constant speed. Lin ran 40 meters and Diego ran 55 meters. 1. Who was m

oving faster?​
Mathematics
1 answer:
Igoryamba3 years ago
5 0

Answer:

Diego ran faster

Step-by-step explanation:

In the ten seconds, Diego ran 15 meters faster than Lin.

55 - 40 = 15

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11 M - 30 from 20 m + 30
Luden [163]

Answer:

11 m - 20 m

Step-by-step explanation:


4 0
3 years ago
Which is an x-intercept of the graph of the function y=cot(3x)
AveGali [126]

Answer:

x-intercept of the graph of the function y = \cot(3x) is, (\frac{\pi}{6} \pm \frac{n\pi}{3} , 0)

Step-by-step explanation:

Given the function: y = \cot(3x)                        ......[1]

x-intercept defined as the graph crosses the x-axis.

Substitute value of y = 0 in [1] and solve for x;

0 = \cot(3x) or

\cot(3x) = 0

Take the inverse cotangent of both sides of the equation and solve for x;

3x = arccot (0)

We know the exact value of arc\cot(0) = \frac{\pi}{2}

then;

3x = \frac{\pi}{2}

Divide both sides by 3 we get;

x = \frac{\pi}{6}

Since, the cotangent function is positive in the first and third quadrants.

The period of the function \cot(3x) is \frac{\pi}{3} so values will repeat every \frac{\pi}{3}  radians in both directions.

we have;

x =\frac{\pi}{6} \pm \frac{n\pi}{3}

Therefore, the x-intercept of the graph of the function y = \cot(3x)  is ;

(\frac{\pi}{6} \pm \frac{n\pi}{3} , 0)  for every integer n;




5 0
3 years ago
Solve using touch points 801+178=
Ierofanga [76]

Answer:

Step-by-step explanation:

979

5 0
3 years ago
A box of coffee is in the shape of a hexagonal prism. Each of the 6 triangles has the same dimension (all triangles are the same
Vinil7 [7]

Answer:

429.9

Step-by-step explanation:

3 0
3 years ago
Use finite approximation to estimate the area under the graph of f(x) = 5^2 and above the graph of f(x) = 0 from X(o) = 0 to x(n
In-s [12.5K]

Finite approximation method of estimating the area under the curve of the

given function makes use of rectangular approximation of the area.

The correct responses are;

i) The estimated area using a lower sum with two rectangles of equal width is <u>1,715 square units</u>.

ii) The estimated area using a lower sum with four rectangles of equal width is <u>3,001.25 square units</u>.

iii) The estimated area using an upper sum with two rectangles of equal width is<u> 8,575 square units</u>.

iv) The estimated area using a upper sum with four rectangles of equal width is <u>6,431.25 square units</u>.

Reasons:

The given function is f(x) = 5·x²

The given domain is x₀ to x₁₄

i) Estimate using lower sum with two rectangles of equal width;

Let \ \Delta x = \dfrac{14}{2} = 7 \ we \ get;

f(0) = 0

f(7) = 5 × 7² = 245

A = 0 × 7 + 245 × 7 = 1,715

The estimated area using a lower sum with two rectangles of equal width

is <u>1,715 square units</u>.

ii) Estimate using lower sum with four rectangles of equal width;

Let \ \Delta x = \dfrac{14}{4} = 3.5 \ we \ get;

f(0) = 0

f(3.5) = 5 × 3.5² = 61.25

f(7) = 5 × 7² = 245

f(10.5) = 5 × 10.5² = 551.25

A = 0 × 3.5 + 61.25 × 3.5 + 245 × 3.5 + 551.25 × 3.5 = 3,001.25

The estimated area using a lower sum with four rectangles of equal width is <u>3,001.25 square units</u>.

iii) Estimate using an upper sum with two rectangles of equal width;

Let \ \Delta x = \dfrac{14}{2} = 7 \ we \ get;

f(7) = 5 × 7² = 245

f(14) = 5 × 14² = 980

A = 245 × 7 + 980 × 7 = 8575

The estimated area using an upper sum with two rectangles of equal width

is <u>8,575 square units</u>.

iv) Estimate using an upper sum with four rectangles of equal width;

Let \ \Delta x = \dfrac{14}{4} = 3.5 \ we \ get;

f(3.5) = 5 × 3.5² = 61.25

f(7) = 5 × 7² = 245

f(10.5) = 5 × 10.5² = 551.25

f(14) = 5 × 14² = 980

A = 61.25 × 3.5 + 245 × 3.5 + 551.25 × 3.5 + 980 × 3.5 = 6,431.25

The estimated area using a upper sum with four rectangles of equal width

is <u>6,431.25 square units</u>.

Learn more here:

brainly.com/question/2264277

4 0
2 years ago
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