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Taya2010 [7]
3 years ago
6

Sophie uses 18 beads to make a necklace. Three-sixths of the beads are purple. How many beads are purple? 6 9 12 15

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

9

Step-by-step explanation:

If 3/6 of the 18 beads are purple we need to simplify 3/6. 3/6 is the same as 1/2. And 1/2 of 18 is 9.

elena55 [62]3 years ago
6 0
The answer is 9 I gotta type 20 characters to give you the answer is 9
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Which table of values includes solutions to the function f(x) = -2x^2?
olga_2 [115]
The table could include values like this:
x     y
-2   -8
-1   -2
0    0
1    -2
2    -8
3 0
3 years ago
PLEASE HELP!!!! 12 POINTS
alexandr1967 [171]

Answer:

12 and 1/4

Step-by-step explanation:


6 0
3 years ago
Manuel made 5 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 5 necklaces
valentinak56 [21]

Answer:

2.3

Step-by-step explanation:

Step 1: Divide 30.50 by 5 to get that each necklaces costs 6.1.

Step 2: Subtract 6.1 (cost for 1 necklace) and 3.80 (price of beads)

Your answer is 2.3! Please mark this as brainliest

4 0
3 years ago
Read 2 more answers
Will mark brainliest!!!plz helppp
muminat

Answer:

(5,-6)

Step-by-step explanation:

ONE WAY:

If f(x)=x^2-6x+3, then f(x-2)=(x-2)^2-6(x-2)+3.

Let's simplify that.

Distribute with -6(x-2):

f(x-2)=(x-2)^2-6x+12+3

Combine the end like terms 12+3:

f(x-2)=(x-2)^2-6x+15

Use (x-b)^2=x^2-2bx+b^2 identity for (x-2)^2:

f(x-2)=x^2-4x+4-6x+15

Combine like terms -4x-6x and 4+15:

f(x-2)=x^2-10x+19

We are given g(x)=f(x-2).

So we have that g(x)=x^2-10x+19.

The vertex happens at x=\frac{-b}{2a}.

Compare x^2-10x+19 to ax^2+bx+c to determine a,b,\text{ and } c.

a=1

b=-10

c=19

Let's plug it in.

\frac{-b}{2a}

\frac{-(-10)}{2(1)}

\frac{10}{2}

5

So the x- coordinate is 5.

Let's find the corresponding y- coordinate by evaluating our expression named g at x=5:

5^2-10(5)+19

25-50+19

-25+19

-6

So the ordered pair of the vertex is (5,-6).

ANOTHER WAY:

The vertex form of a quadratic is a(x-h)^2+k where the vertex is (h,k).

Let's put f into this form.

We are given f(x)=x^2-6x+3.

We will need to complete the square.

I like to use the identity x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2.

So If you add something in, you will have to take it out (and vice versa).

x^2-6x+3

x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2

(x+\frac{-6}{2})^2+3-3^2

(x+-3)^2+3-9

(x-3)^2+-6

So we have in vertex form f is:

f(x)=(x-3)^2+-6.

The vertex is (3,-6).

So if we are dealing with the function g(x)=f(x-2).

This means we are going to move the vertex of f right 2 units to figure out the vertex of g which puts us at (3+2,-6)=(5,-6).

The y- coordinate was not effected here because we were only moving horizontally not up/down.

3 0
3 years ago
Drag each expression to show whether it is equivalent to 36 + 9, 9(4 – 1), or (4 • 9) + (4 • 2).
EastWind [94]

Answer:

None of these are equivalent

Step-by-step explanation:

36 + 9 = 45

9(4 – 1) = 9* 3 = 27

 (4 • 9) + (4 • 2) = 36+ 8 = 44

7 0
3 years ago
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