For the function f(x) = -2(x + 3)^2 -1, identify the vertex, domain, and range. A.) The vertex is (3, -1), the domain is all rea
l numbers, and the range is y ≥ -1. B.) The vertex is (3, -1), the domain is all real numbers, and the range is y ≤ -1. C.) The vertex is (-3, -1), the domain is all real numbers, and the range is y ≤ -1. D.) The vertex is (-3, -1), the domain is all real numbers, and the range is y ≥ -1
Ok so domain is all allowed numbers
look at deonomenator and don't allow any numbers that will make it zero
none
that means
domain=all real numbers
vertex
in form
y=a(x-h)^2+k
(h,k)=vertex
we have
y=-2(x+3)^2-1
h=-3
k=-1
vertex=(-3,-1)
range
the vertex opens down so max is y=-1
y≤-1
domain is all real
vertex is (-3,-1)
y≤-1
C
