Answer:
30 years
Step-by-step explanation:
2 is a factor of 30, so the LCM of 2 and 30 is 30.
Saturn and Mars will appear in the same direction in the night sky every 30 years.
Answer: Lesser = 19, Greater = 21
See picture reply.
Answer:0.369 m
Step-by-step explanation:
Given
Distance between slit and screen is 
Wavelength 
Angle between zeroth order bright fringe and Fourth-order bright fringe is 
let distance between the slits be d
Distance of n th bright fringe From central Fringe is given by
Also 
Answer:
1. 9/10
2. 15/16
4. 3/5
5. 3/5
Step-by-step explanation:
1. 7/10 + 2/10 = 9/10
2. 13/16 + 2/16 = 15/16
4. 7/15 + 2/15 = 9/15 = 3/5
5. 9/20 + 3/20 = 12/20 = 3/5
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
