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Elis [28]
2 years ago
9

HELP I AM TIMED!!!!!!!!!!!!

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
5 0
Answer:

It is the last one 6a-4b+11

Explanation:

Hope this helps if u need clarification plz ask:)
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How to solve this one​
nalin [4]

Answer:

Step-by-step explanation:

w^3 + 4w^2 + 5w - 12

3 0
3 years ago
Read 2 more answers
15/3 + (6,5 + 4,2) - 0,6 <br><br> Please show your work, thank you :)
kifflom [539]

Answer:

15/3 + (6.5 + 4.2) - 0.6 = 15.1

Step-by-step explanation:

You can first reduce the fraction to 5 when you multiply by 3, then calculate what's in the parenthesis. So now you have 5 + 10.7 - 0.6, then just solve from left to right. Hope this helps

3 0
2 years ago
What is 7/8 x c for c =8
3241004551 [841]
7/8 × c ⇒ substitute ⇒ turn 8 into a fraction

  7         8            56
___ ×  ___  =   _____ = 7
              
  8          1             8

Your answer is 7

5 0
3 years ago
Read 2 more answers
A student was given two data sets, Set A and Set B. Which of the following statements is true?​
guajiro [1.7K]

D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A jar contains 4 white and 4 black marbles. We randomly choose 4 marbles. If 2 of them are white and 2 are black, we stop. If no
Airida [17]

Answer:

<em>Find the probability of success in a single trial and then think about the nature of the problem (when do we stop).  </em>

Step-by-step explanation:

Observe that in the single trial, we have (8 4) possibilities of choosing our set of balls. If we have chosen two white balls and two black balls, the probability of doing that is simply  

p=(4 2)*(4 2)/(8 4)

This is well know Hyper geometric distribution. Now, define random variable X that marks the number of trials that have been needed to obtain the right combination (two white and two black balls). From the nature of the problem, observe that X has Geometric distribution with parameter p that has been calculated above. Hence  

P(X = n) = (1— p)^n-1 *( p )

<em>Find the probability of success in a single trial and then think about the nature of the problem (when do we stop).  </em>

3 0
3 years ago
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