<span>Fossil fuels contain "Chemical energy" stored millions of years ago.
In short, Your Answer would be: "False"
Hope this helps!</span>
-493.4138 that's what I got when you subtract 15.54 from 508.9538
<span>Answer:
Yes, I get 17 rad/s², too.
Note that the assumption of constant angular acceleration is really, really, terrible. A valid answer to this question (i.e., one that does not assume constant angular acceleration) involves differential equations. But if you do assume constant angular acceleration, this is quite straightforward. Use constant-acceleration kinematics:
Δθ = ω_i Δt + ½α (Δt)²
You know the pencil moves through an angle of π/2 radians. The initial angular velocity is zero. You already found the angular acceleration, and you want Δt.
Δt = âš[ 2 Δθ / α ] = âš[ 2 (Ď€/2 rad) / 17 rad/s² ] = 0.34 s
This is the same calculation oldprof makes, but his treatment of the pencil as a point mass rather than a uniform rod has thrown his angular acceleration off.</span>
Answer:
60 m
Explanation:
Arthur and Betty will be walking for the same amount of time t
Speed of Arthur = 3 m/s
Speed of Betty = 2 m/s
Distance = Speed × time
Distance covered by Arthur = 3t
Distance covered by Betty = 2t
Distance that Arthur and Betty will cover will be 100 m
3t+2t = 100
⇒5t = 100
⇒t = 100/5
⇒t = 20 s
So, Arthur and Betty will be walking for 20 seconds
Spot is by Arthur's side and keeps running in between them until they meet. So, Spot will be running for 20 seconds and the displacement covered will be the distance covered by Arthur which is
3t = 3×20 = 60m
Displacement is the shortest distance between two points so, Spot's displacement will be 60 m
Answer
given,
mass of car (m) = 1200 Kg
speed of cur, u = 25 m/s
mass of truck(M) = 9000 Kg
speed of truck, u' = 20 m/s
v = 18 m/s
a) using conservation of momentum
m u + M u' = m v + M v'
1200 x 25 + 9000 x 20 = 1200 x 18 + 9000 x v'
9000 v' = 188400
v' = 20.93 m/s
b) To calculate losses, we will find the kinetic energies before & after collision. Any difference would give us the losses (in energy form).
(K E)₁= (K E)₂+ Losses
losses = (K E)₂ - (K E)₁
=
=
=9038 J