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hjlf
1 year ago
14

A small, closed chamber of gas is heated. When the gas in the chamber expands,it does 5 J of work on a piston. The gas has an in

itial energy of 8J and a finalenergy of 30 J. Considering the equation for the firsI law of thermodynamics (AU=Q+W), does the work done in this scenario have a positive or negative value?
Physics
1 answer:
Anestetic [448]1 year ago
3 0

Given:

Work done, W = 5 J

Initial energy = 8J

Final energy = 30J

Let's determine if the work done have a positive or nrgative value.

Appy the equation for the first lae of thermodynamics:

\Delta U=Q-W

Where:

U is the change in internal energy

Q is the added heat

W is the work done

To find the work done here, we have:

Rewrite the formula for W

W=Q-\Delta U

Where:

ΔU = 30J - 8J = 22J

Q = 5J

Thus, we have:

\begin{gathered} W=5J-22J \\  \\ W=-17J \end{gathered}

Therefore, the work done here is -17J.

This means the work done in this scenario has a negative value.

ANSWER:

The work done in this scenario has a negative value

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The velocity of the current in a river has no effect on the the time it takes to paddle a canoe across the river, given that the boat is pointed perpendicular to the bank of the river, because

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Reason:

Let \overset \rightarrow {v_y} represent the velocity of the boat across the river in the direction, \overset \rightarrow {d_y}, and let, \overset \rightarrow {v_x}, represent the velocity of the river, we have;

The velocity of the boat perpendicular to the direction of the river = \overset \rightarrow {v_y}

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This is so because the velocity in the perpendicular direction to the flow of

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\overset \rightarrow {v_y} = 3 m/s

\overset \rightarrow {v_x} = 4 m/s

The width of the river, w_y = 6 meters, we have;

  • The resultant velocity = \sqrt{(3 \ m/s)^2 + (4 \ m/s)^2} =5 \ m/s

The direction, θ, is given as follows;

\theta = \arctan \left(\dfrac{4}{3} \right) \approx 53.13^{\circ}

The length of the path of the boat, <em>l</em>, is given as follows;

l = \dfrac{6}{cos \left(\arctan \left(\dfrac{4}{3} \right)\right)} = 10

The length of the path the boat takes = 10 m

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t = \dfrac{w_y}{v_y}

Therefore;

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Answer:

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