Question

A hockey puck with a mass of 0.17 kg is traveling to the right along the ice at 15 m/s. it strikes a second hockey puck with a mass 0.11 kg. the first hockey puck comes to rest after the collision. What is the velocity of the second hockey puck after the collision? ( Round your answer to the nearest integer.)

Answer 1

Answer:

$v_2 = 23.182m/s$

Explanation:

Given

$m_1 = 0.17kg$

$m_2 = 0.11kg$

$u_1 = 15m/s$ -- Initial Velocity of the first

$u_2 = 0m/s$ -- Initial Velocity of the second

$v_1 = 0m/s$ -- Final Velocity of the first

Required

Determine the final velocity of the second hockey puck ($v_2$)

This question illustrates law of conservation of momentum and it'll be solved using the following formula:

$m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2$ ---- law of conservation of momentum

Substitute in the right values

$0.17 * 15 + 0.11*0 = 0.17 * 0 + 0.11*v_2$

$0.17 * 15 + 0 = 0 + 0.11*v_2$

$2.55 = 0.11*v_2$

Solve for v2

$v_2 = 2.55/0.11$

$v_2 = 23.182m/s$

Hence, the final velocity of the second hockey puck is 23.182m/s