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WINSTONCH [101]
3 years ago
12

Suppose the universe were completely empty except for one object- a solid sphere moving through space at a speed of 100km/s. wha

t sort of path would the object be moving in?
Physics
1 answer:
vladimir2022 [97]3 years ago
8 0

Straight linear path

Explanation:

If the universe were completely empty with just one object which is solid moving sphere  through the space at a speed of 100km/s, it will move along on a straight path.

An object will continue on a straight path or at rest unless acted upon by an external force. This is the first law of newton.

  • Since there is no other mass or body in the universe, it will move along in a straight line.
  • Our planet and other bodies moves in parabolic path and elliptical orbits because they are attracted by the gravitational forces of other bodies.
  • Any body with mass will attract other bodies and makes it move round it.
  • The body with the less mass will orbit in the vicinity of the larger mass.
  • But if we have just one body out there, there is no attraction from any other body, it will continue along it's straight path.

learn more:

Gravitational force brainly.com/question/4417434

#learnwithBrainly

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3 years ago
Which colors of light represents the lowest visible frequency?
kodGreya [7K]

Answer:

Red

Explanation:

Red is a colour which has the lowest frequency. Violet has the highest frequency. Frequency has a direct relationship with energy. This means the higher the frequency, the higher the energy. Red has the lowest energy of all the colors too.

The frequency and Energy has an inverse relationship with the wavelength.

However Red has the longest wavelength of about 620 - 780 nanometer.

3 0
3 years ago
A dog runs 30 feet to the north then 5 feet to the south what is the displacement of the dog
Nuetrik [128]
To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.
5 0
3 years ago
Read 2 more answers
A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
vladimir1956 [14]

a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

5 0
3 years ago
Based on the diagram which of the following traits come before shearing teeth?
Sliva [168]

Answer:

where is the diagram

Explanation:

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