A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
A and C I’m pretty sure D is also equivalent to 5.
Answer: 2 over 1
Step-by-step explanation: Division and cause i am in Honors Geometry high school
Okay. I’m no mathematician, but I’m pretty sure it would be 995/90 = h. I used the “/” as the divide symbol. This would be the equation because you need to divide the total by the cash per hour to be able to get the number of hours the plumber worked. I really hope this helps!
False, for example, if the scale factor is 2, the scale drawing would still be smaller because it would be twice as smaller than the actual object.
