HELP what number is equal to -9 x(-1/3) A.-27 B.-3 C.3 D.27

Help please!!!!!!!!!!!!!!!!!!!!

vfiekz [6]

Step-by-step explanation:

the calculation is included. I hope its self explanatory

8 0

1 year ago

An invoice is dated January 17 with terms of 8/10 , 6/20 , 4/30 , n/40 . find the three final discount dates and the net payment

IRISSAK [1]

Invoice Date = January 17

• First terms:

8/10 and n/40

This means the final discount can be availed "10" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 10 days = January 27

Final Discount Date = Jan 27

The net payment date will be "n/40", which is 40 days from invoice date, thus

Net payment date will be:

Jan 17 - Jan 31 = 14 days

Feb 1 - Feb 26 = 26 days

------------------------------------

40 days

Payment Date = Feb 26

• Second terms:

6/20 and n/40

This means the final discount can be availed "20" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 20 days = Feb 6

Final Discount Date = Feb 6

The net payment date will be "n/40", which is 40 days from invoice date, thus, same as before,

Payment Date = Feb 26

• Third terms:

4/30 and n/40

This means the final discount can be availed "30" days from Invoice Date (Jan17)

So, it will be:

Jan 17 + 20 days = Feb 16

Final Discount Date = Feb 16

The net payment date will be "n/40", which is 40 days from invoice date, thus, same as before,

Payment Date = Feb 26

6 0

9 months ago

What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

Kitty [74]

Answer:

$-\frac{3p^8}{4q^3}$

Step-by-step explanation:

$\frac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}}$ can be broken down into three fractions, coefficients, powers of p, powers of q.

$-\frac{15}{20}\cdot\frac{p^{-4}}{p^{-12}}\cdot\frac{q^{-6}}{q^{-3}}$

Simplify the first fraction, then simplify the others by subtracting numerator exponents minus denominator exponents.

$-\frac{3}{4} p^{-4-(-12)} q^{-6-(-3)} =-\frac{3}{4} p^8 q^{-3} = \alpha -\frac{3p^8}{4q^3}$

8 0

2 years ago

What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3

Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

= 11 × 8

= 88 square units

Area of trapezoid OGEF = $\frac{1}{2}(b_1+b_2)\times h$

= $\frac{1}{2}(\text{GE+OF)}\times (\text{OG})$

= $\frac{1}{2}(3+6)\times 4$

= 18 units²

Area of trapezoid GCDE = $\frac{1}{2}(\text{GC+DE)}\times (\text{GE})$

= $\frac{1}{2}(7+2)\times 3$

= 13.5 units²

Area of triangle AFH = $\frac{1}{2}(\text{Base})\times (\text{Height})$

= $\frac{1}{2}(5)(2)$

= 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

= 88 - (18 + 13.5 + 5)

= 88 - 36.5

= 51.5 units²

Therefore, area of the given polygon is 51.5 units²

3 0

2 years ago

Find the solution in slope-intercept form y+7=-3(x-1) and 3x+y=-4

Svetach [21]

Answer:

The slope intercept form of both given equations is : y = - 3 x - 4.

Step-by-step explanation:

Here, the given equations are:

y +7 = -3 ( x - 1 )

and 3 x + y = - 4

Now,the SLOPE INTERCEPT FORM of any given equation is given as:

y = m x + C : here, C = Y - intercept, m = Slope

Consider equation (1):

y +7 = -3 ( x - 1 ) ⇒ y + 8 = - 3 x + 3

or, y = -3x + 3 - 7 = -3x - 4

⇒ y = -3x -4

Hence, the slope-intercept form of the given equation is y = -3x -4.

Consider equation (2):

3 x + y = - 4 ⇒ y = -4 - 3 x

⇒ y = -3 x - 4

Hence, the slope-intercept form of the given equation is y = -3x -4.

6 0

2 years ago