HELP what number is equal to -9 x(-1/3) A.-27 B.-3 C.3 D.27

Mathematics

1 answer:

gladu [14]2 years ago

3 0

Answer:

The correct answer is letter C

Step-by-step explanation:

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Solve for x. −13x≤−6

AfilCa [17]

−13 x ≤ − 6

Step 1: Divide both sides by -13.

−13x/−13 ≤ −6/−13x ≥ 6/13

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2 years ago

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What is the following quotient? square root 6 + square root 11 / square root 5 + square root 3

Sladkaya [172]

Answer:

Decimal: 5.66478

Step-by-step explanation:

√6 + √11 / √5 + √3

= √3 + 1/5 √55 + √6

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2 years ago

What is the slope and y-intercept for the line represented by this equation?

alexira [117]

5x + 13y = -13
13y = -5x - 13
y = -5/13x - 13/13
y = -5/13x - 1

Slope = -5/13
y-intercept = -1

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2 years ago

Over the interval 2 to 4 by how much does the function increase. explain

deff fn [24]

The function increases by by 2 because of yo ylook at it 2+2=4 and well backwards 4-2=2 so the answer is 2. Hope hat made a lot of sense and that it helped you a lot with your problem and answer

4 0

3 years ago

Find the equation of the circle that has a diameter with endpoints located at (7, 3) and (7, –5).

posledela

So hmm check the picture below, that's about the circle and the endpoints, but notice, the endpoints make up a segment, namely the diameter of the circle, well.... let's see how long that is, because, the radius is half the diameter

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 7}}\quad ,&{{ 3}})\quad 
% (c,d)
&({{ 7}}\quad ,&{{ -5}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(7-7)^2+(-5-3)^2}\implies d=\sqrt{0+(-8)^2}\implies d=8
\\\\\\
\textit{the radius is half that, so is }\boxed{r=4}$

now.. hmmm notice, the midpoint of the diameter, is the center of the circle, let's check that one out

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 7}}\quad ,&{{ 3}})\quad 
% (c,d)
&({{ 7}}\quad ,&{{ -5}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ 7+7}}}{2}\quad ,\quad \cfrac{{{ -5}} + {{ 3}}}{2} \right)\implies \left( \cfrac{14}{2}\ ,\ \cfrac{-2}{2} \right)\implies \boxed{(7,-1)}$

now.. that we know what the center is, and what the radius is, well

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k\quad }})\qquad 
radius=&{{ r}}\\
&7&-1&4
\end{array}$

5 0

3 years ago