Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)
The values of the cummulative distribution function of the standard Normal random variable, lets denote it are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600
Hence, the proportion of scores reported as 1600 is 0.0032.
Answer:
The answer is in attached picture.
Step-by-step explanation:
#Hope it helps uh........
Answer:
top left
Step-by-step explanation:
-60<u><</u>5(x-12)<-40 (v)
5(x-12)=5x-60
-60<u><</u> 5x -60< -40 (v)
solve the first half of the equation
-60 <u><</u> 5x making x <u>></u> 12
solve the second half of the equation
-60 < -40 add 60 to both sides of the second inequality and that would get u an answer a final answer of 20 on that half. i dont know how to go from there for the fact that i cant see whats on the graph .
It's a linear function: y = mx + b.
The graph of the linear function is a straight line. Two points are enough for plotting a graph of this function.
The domain of this function is
We have the function: y= 3x - 6
We choose any two x and calculate the value of y:
for x = 0 → y = 3(0) - 6 = 0 - 6 = -6 → (0, -6)
for x = 2 → y = 3(2) - 6 = 6 - 6 = 0 → (2, 0)