We can write and solve the differential equation that fits the statement given;
dy/dt = k(50-t)
∫dy = ∫ k(50-t)dt
= ∫ (50k - kt) dt
therefore;
y = 50kt - k/2(t²) + C
Alternatively, can be written as
y = - k/2 (50-t)² + C)

3 0

3 years ago

What is y={-\dfrac{1}{3}}x-9y=− 3 1 x−9y, equals, minus, start fraction, 1, divided by, 3, end fraction, x, minus, 9 written i

Kobotan [32]

Answer:

$x+3y=-27$

Step-by-step explanation:

We are given that

$y=(-\frac{1}{3})x-9$

We have to find the standard form of given equation

$y=\frac{-x-27}{3}$

$3y=-x-27$

By using multiplication property of equality

$x+3y=-27$

We know that

Standard form of equation

$ax+by=c$

Therefore, the standard form of given equation is given by

$x+3y=-27$

5 0

3 years ago