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Debora [2.8K]
3 years ago
14

F(x)=4x+2 and g(x)=4(x−9)+2. What transformation occurs from function f to function g? a translation 9 units right a horizontal

compression by a factor of 9 a horizontal stretch by a factor of 9 a translation 9 units down
Mathematics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

A translation 9 units right

Step-by-step explanation:

Given

f(x) = 4x + 2

g(x) = 4(x -9)+ 2

Required

Translation of f(x) to g(x)

To do this, we take the options one after the other.

A translation 9 units right

When an original function f(x) is translated to the right by h points, the resulting function g(x) is

g(x) = f(x - h)

So, we have that:

f(x) = 4x + 2

When translated to the right by 9 points,

g(x) = 4(x - 9) + 2

<em>Hence, option A answers the question</em>

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Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

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f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

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f(\frac{2x+1}{x} )=1

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g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

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B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

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Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



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