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2 years ago

I need help on this please

Mathematics

1 answer:

irakobra [83]2 years ago

4 0

The answer is C :$396.00

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Academy sporting goods store sells two different models of a popular

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Answer:

I SUCK AT WORD PROBLEMS TOOOO LOL

Step-by-step explanation:

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2 years ago

1.) The Difference between seven times one number and three times a second number is 25. The sum of twice the first and five tim

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3 years ago

Which shape is a parallelogram?<br><br> I’ll mark you if you give the right answer!!

Lilit [14]

Answer:

The rectangle is a parallelogram.

Step-by-step explanation:

Parallelograms are shapes with two pairs of parallel sides.

The rectangle is the only shape that meets those requirements.

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2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

Factor 10z + 45.<br> i need help!

disa [49]

Answer:

5(2z +9)

Step-by-step explanation:

factor out 5 of 10z +45

3 0

2 years ago