Answer:
23430.4 J.
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 70 g
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 90 – 10
ΔT = 80 °C
Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:
Mass (M) = 70 g
Change in temperature (ΔT) = 80 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Q = MCΔT
Q = 70 × 4.184 × 80
Q = 23430.4 J
Therefore, 23430.4 J of heat energy is required to heat up the water.
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First find the moles of CO3.
Answer:
A bohr developed a model of atom that predicts how it will behave.
Answer:
0.075 M
Explanation:
5Fe²⁺(aq) + MnO₄⁻(aq) + 8H⁺(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(ℓ)
Using the moles of Fe²⁺ that reacted, we can <em>calculate the reacting moles of MnO₄⁻</em>:
0.0450 mol Fe⁺² * 
= 0.0090 mol MnO₄⁻
Now we divide the moles of MnO₄⁻ by the volume in order to <u>calculate the molarity of the solution</u>, keeping in mind that 120.0 mL = 0.120 L.
0.0090 mol MnO₄⁻ / 0.120 L = 0.075 M
