<u>Answer:</u>
<u>For a:</u> Work done for the given reaction is 2477.572 J.
<u>For b:</u> Work done for the given reaction is 0 J
<u>Explanation:</u>
To calculate the work done for the reaction, we use the equation:
Ideal gas equation follows:
Relating both the above equations, we get:
......(1)
where,
= difference in number of moles of products and reactants = 
R = Gas constant = 8.314 J/K.mol
T = temperature = ![25^oC=[273+25]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5DK%3D298K)
The chemical reaction follows:
Putting values in equation 1, we get:
Hence, work done for the given reaction is 2477.572 J.
The chemical reaction follows:
Putting values in equation 1, we get:
Hence, work done for the given reaction is 0 J.
The number of hydrogen atoms that are in 7.80 moles of ammonium sulfide are 3.756 x 10^25 atoms
<u>calculation</u>
Step 1: calculate the moles of H in (NH4)2S
since there are 8 atoms of H in (NH4)2S the moles of
H = 8 x7.80 = 62.4 mole
Step 2: use of Avogadro's law constant to determine the number of H atom
that is 1 mole = 6.02 x10^23 atoms
62.4 moles=? atoms
= [ 62.4 x 6.02 x10^23]/ 1 mole= 3.756 x10^25 atoms
Answer:
option A is correct answer of this question
hope it helps and your day will be full of happiness
The number above the symbol is the atomic mass (or atomic weight). This is the total number of protons and neutrons in an atom. The number below the symbol is the atomic number and this reflects the number of protons in the nucleus of each element's atom. Every element has a unique atomic number.
The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.
<h3>What is empirical formula?</h3>
The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.
<h3>
How to find the empirical formula?</h3>
Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.
Moles phosphorus = 0.903 g phosphorus 
= 0.0293 mol
Moles bromine 6.99 g bromine
=0.0875 mol
The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3
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