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3 years ago

HELP!!!!

Chemistry

1 answer:

LenKa [72]3 years ago

6 0

Answer:

The correct answer is: Only Reaction 1.

Explanation:

Ok, let us define what entropy is: entropy is a measure of the random activity in a system, and there are several factors which can affect the amount of entropy in a system - for example when you increase temperature, you increase entropy.

In this case,

Reaction 1: NaCl(s) → Na+(aq)+Cl- (aq): In this reaction you are solvating the atoms of Na+ and Cl-, or in other words, you are passing a compound from the solid state to the liquid state, which causes the entropy to increase. Liquids have more energy and entropy than solids.

Reaction 2: N2(g) + 3H2(g) → 2NH3(g): In this case you are getting a gaseous product from gaseous reactants, and although there is positive entropy, it does not increase.

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Consider an exceptionally weak acid, HA, with a Ka = 1x10 -20 . You make a 0.1M solution of the salt Na

Vedmedyk [2.9K]

Answer:

$pH=13$

Explanation:

Hello,

In this case, given the acid, we can suppose a simple dissociation as:

$HA\rightleftharpoons H^+ + A^-$

Which occurs in aqueous phase, therefore, the law of mass action is written by:

$Ka=\frac{[H^+][A^-]}{[HA]}$

That in terms of the change $x$ due to the reaction's extent we can write:

$1x10^{-20}=\frac{x*x}{0.1M-x}$

But we prefer to compute the Kb due to its exceptional weakness:

$Kb=\frac{Kw}{Ka}=\frac{1x10^{-14}}{1x10^{-20}} =1x10^{-6}$

Next, the acid dissociation in the presence of the base we have:

$Kb=\frac{[OH^-][HA]}{[A^-]}=1x10^{6}=\frac{x*x}{0.1-x}$

Whose solution is $x=0.0999M$ which equals the concentration of hydroxyl in the solution, thus we compute the pOH:

$pOH=-log([OH^-])=-log(0.0999)=1$

Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:

$pH+pOH=14\\\\pH=14-pOH=14-1\\\\pH=13$

Regards.

5 0

3 years ago

Read 2 more answers

WHAT IS NORMAL MUSCLE PH

larisa [96]

The skeletal muscle ph is typically 7.15

8 0

2 years ago

Consider the following equilibrium:

Ainat [17]

<u>Answer: </u>The equation which is wrong is $K_p=K_c(RT)^{-5}$

<u>Explanation:</u>

For the given reaction:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

The expression for $K_c\text{ and }K_p$ is given by:

$K_c=\frac{1}{[O_2]^3}$

$K_p=\frac{1}{[O_2]^3}$

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between $K_p\text{ and }K_c$ is given by the expression:

$K_p=K_c\times (RT)^{\Delta n_g}$

where,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for $K_p$ is:

$K_p=K_c\times (RT)^{-3}$

Therefore, the equation which is wrong is $K_p=K_c(RT)^{-5}$

7 0

3 years ago

A medication 60 mg is ordered. the vial is labeled 1 gm/ 10 ml. How many ml would you give?

timofeeve [1]

I believe it is 6ml because you do the doseage times the ml and mutiply it by 1

4 0

3 years ago

25) Which of the following would exert the most pressure on the ground? 3 points

Zarrin [17]

Answer:

a women standing in high heels

Explanation:

8 0

2 years ago

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