It is any fraction except 0 of 180°.
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To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
Answer:
<em>a = 6 </em>
Step-by-step explanation:
g(x) = 5x - 2
h(x) = √(x + 3)
g(h(x)) = 5
- 2
g(h(a)) = 5
- 2
5 - 2 = 13
5 = 15
= 3
( )² = 3²
a + 3 = 9
<em>a = 6</em>
Answer:
Step-by-step explanation:
See attachment 1. This is the formula to use.
There are two numbers, so n=2. Plugging them into the formula, you get
![\sqrt[2]{6*\frac{1}{2}} \\](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B6%2A%5Cfrac%7B1%7D%7B2%7D%7D%20%5C%5C)
Now, putting a 2 in front just means we're finding the square root, so I'll get rid of it. Then, just do the calculation.
