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Rainbow [258]
3 years ago
11

Find the common difference of the sequence shown. 1/6 , 1/3 , 1/2 , 2/3 , ... 1/12 1/6 1/3

Mathematics
2 answers:
swat323 years ago
7 0
I'll write my answer in here 1/6
bogdanovich [222]3 years ago
4 0
<h2>Answer</h2>

The common difference of the sequence is \frac{1}{6}

<h2>Explanation </h2>

The term "common difference" is telling us that our sequence is arithmetic. To find the common difference of an arithmetic sequence, we use the formula: d=a_{n}-a_{n-1}

where

d is the common difference

a_{n} is the current term in the sequence

a_{n-1} is the previous term in the sequence

In other words, the formula is telling us that to find the common difference, we subtract the previous term in the sequence form the current term in the sequence.  

Let's find the difference for 1/6 , 1/3:

a_{n}=\frac{1}{3} and a_{n-1}=\frac{1}{6}

d=a_{n}-a_{n-1}

d=\frac{1}{3}-\frac{1}{6}

d=\frac{1}{6}

Let's make sure that the difference holds across the sequence by repeating the process for 1/3 , 1/2

a_{n}=\frac{1}{2} and a_{n-1}=\frac{1}{3}

d=\frac{1}{2}-\frac{1}{3}

d=\frac{1}{6}

And finally, for 1/2 , 2/3

a_{n}=\frac{2}{3} and a_{n-1}=\frac{1}{2}

d=\frac{2}{3}-\frac{1}{2}

d=\frac{1}{6}

We can conclude that the common difference of the sequence shown is \frac{1}{6}


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