Im pretty sure the answer is 65
Answer: C=[ (10) x (19.60)÷ (8)]
Step-by-step explanation:
Given , The cost of 8 books = $ 19.60
Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)
i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)
Now , cost of 10 books = (10) x (Cost of one book)
From (i) , we get
Cost of 10 books =$[ (10) x (19.60)÷ (8)]
Let C be the cost of 10 books ( in dollars) .
So , the equation would help determine the cost of 10 :
C=[ (10) x (19.60)÷ (8)]
-9-6+12h+40=22
12h+25=22
12h=-23
h=-23/12
The number of the product is 9
10d+ 25q+5n= 805
D= n+8
Q= n+ 5
10d+ 25q+5n= 805
10(n+8)+25(n+5)+5n=805
10n+80+25n+125+5n=805
40n+205=805
40n=805-205
40n= 600
N=600/40
N= 15
D= n+8
D= 15+8
D= 23
Q=n+5
Q=15+5
Q=20
So 15 nickels ,23 dimes and 20quarters .
To check
15(0.05)= $0.75
23(0.10)=$2.30
20(0.25)=$5.00
Add it
5.00+2.30+0.75=8.05
7.30+.75=8.05
8.05=8.05
