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3 years ago

How do you solve w=120(1/3) by step

Mathematics

1 answer:

lubasha [3.4K]3 years ago

6 0

Answer:

w=40

Step-by-step explanation:

120*1/3=40

Therefore, w=40

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<img src="https://tex.z-dn.net/?f=3x%2B14%5Cleq%2013" id="TexFormula1" title="3x+14\leq 13" alt="3x+14\leq 13" align="absmiddle"

emmasim [6.3K]

Answer:

x ≤ - $\frac{1}{3}$

Step-by-step explanation:

Given

3x + 14 ≤ 13 ( subtract 14 from both sides )

3x ≤ - 1 ( divide both sides by 3 )

x ≤ - $\frac{1}{3}$

8 0

3 years ago

Read 2 more answers

Rounding to the nearest ten

REY [17]

10, because 10 does not need to be rounded to the nearest 10 if the number is already 10, but if the number was 17 then rounding to the nearest 10 would be 20

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3 years ago

EASY QUESTIONS FOR EASY POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!

Sauron [17]

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2 years ago

A cyclist rode for 3.5 hours and completed a distance of 60.9 miles. If she kept the same average speed for each hour, how far d

SVETLANKA909090 [29]

divide total miles by total time:

60.9 / 3.5 = 17.4 miles per hour

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3 years ago

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Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to

MrRissso [65]

Answer:

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

$\mu=0.375\\\\\sigma^2=0.347$

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

$p=3/40=0.075$

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

$P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275$

b) The mean and variance of defective components in the sample is:

$\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347$

The Chebyschev's inequality established:

$P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}$

6 0

3 years ago