Given:
W(width) = (6L) - 9
L(length) = L
Equation:
2( [ 6L ] - 9) + 2 (L) = 150
= 12L - 18 + 2L = 150
= 12L + 2L = 150 + 18
=14L = 168
L = 168/14, so the length is 12. Let's check our work.
Width: 6(12) - 9 = 72 - 9 = 63
Length: 12
Since there are two lines of width and two lines of length:
2(12) + 2(63) = 24 + 126, which gives you a perimeter of 150 mm.
Hope this helped.
Good question next quetionn
Answer:
75°
Step-by-step explanation:
![m\angle KLM=m\angle KLQ+m\angle QLM \\ \\ 173=x+105+x+82 \\ \\ 173=2x+187 \\ \\ 2x=-14 \\ \\ x=-7 \\ \\ \implies m \angle QLM=-7+82=75^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3Dm%5Cangle%20KLQ%2Bm%5Cangle%20QLM%20%5C%5C%20%5C%5C%20173%3Dx%2B105%2Bx%2B82%20%5C%5C%20%5C%5C%20173%3D2x%2B187%20%5C%5C%20%5C%5C%202x%3D-14%20%5C%5C%20%5C%5C%20x%3D-7%20%5C%5C%20%5C%5C%20%5Cimplies%20m%20%5Cangle%20QLM%3D-7%2B82%3D75%5E%7B%5Ccirc%7D)
3) 3.sec² Ф = 4.tan² Ф
but sec² Ф = 1/cos² Ф
3/cos² Ф = 4.tan² Ф
3/4 = (tan² Ф).(cos² Ф) ; tan² Ф = sin² Ф/cos² Ф
3/4 = (sin² Ф)x(cos² Ф)/(cos² Ф)
sin² Ф = 3/4
a) sin Ф = +(√3)/2 and b) sin Ф = - (√3)/2
sin Ф = + - (√3)/2 → Ф =π/3 + kπ/3